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36x^2-60x+25+16x^2-64=0
We add all the numbers together, and all the variables
52x^2-60x-39=0
a = 52; b = -60; c = -39;
Δ = b2-4ac
Δ = -602-4·52·(-39)
Δ = 11712
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11712}=\sqrt{64*183}=\sqrt{64}*\sqrt{183}=8\sqrt{183}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-8\sqrt{183}}{2*52}=\frac{60-8\sqrt{183}}{104} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+8\sqrt{183}}{2*52}=\frac{60+8\sqrt{183}}{104} $
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